edward lansing
Advanced Member
This thread will discuss the considerable forces in the hydraulic system. I am trying to give everyone a feel for what the cylinder is capable of when it gets moving. OK, stick with me for a moment.
1. For my 1702T the UVW (unloaded vehicle weight ) is 2690 lb.
2. How much does the top weigh? I guess about 40% or 1200 lbs. From jacking it up a few times in the ball park.
3. Each cable carries 1/4 of the total or 1200/4= 300lbs.
4. At the pulley head, each cable wraps around 180 degrees so the head sees a load of 600 lbs or 300*2=600 lbs.for each pulley.
5. There are 4 pulleys so the total load on the head needed to hold the top up is 600*4= 2400 lbs.
6. To actually raise the top there are friction forces, fluid pressure losses, etc. So lets say another 50%. The cylinder now has to put out about 2400 lbs * 1.5 or 3600 lbs. This is what a car or small truck weighs.
7. My cylinder is about 3" diameter or the piston has a dia of about 2 3/4 inches. This is an area of 6 sq in.
8. To put out a force of about 3600 lbs on 6 sq in you need a pressure from the pump of 600 psi. The book says the pump is good for up to 3000 psi so it looks OK so far.
9. The relief valve is set over 600 psi and I wish I could call the factory, let us guess that it is 1200psi give or take. Note that 1200 psi over 6 sq in is a force of 7200 lbs or 3.6 tons. A bunch.
10. If the relief valve is stuck or jammed the pump could put out 3000 psi. Over 6 sq in this is 18000 lbs or 9 tons. Think Godzilla under the trailer grinding things up!
Considerable forces. I can now see that if the cylinder gets jammed or stuck, there are considerable forces generated the could easily bend or distort guide rods and cylinders. In Part III I will try to explain what I found in my removal, repair process. How can these rods get so bent up? More later.
1. For my 1702T the UVW (unloaded vehicle weight ) is 2690 lb.
2. How much does the top weigh? I guess about 40% or 1200 lbs. From jacking it up a few times in the ball park.
3. Each cable carries 1/4 of the total or 1200/4= 300lbs.
4. At the pulley head, each cable wraps around 180 degrees so the head sees a load of 600 lbs or 300*2=600 lbs.for each pulley.
5. There are 4 pulleys so the total load on the head needed to hold the top up is 600*4= 2400 lbs.
6. To actually raise the top there are friction forces, fluid pressure losses, etc. So lets say another 50%. The cylinder now has to put out about 2400 lbs * 1.5 or 3600 lbs. This is what a car or small truck weighs.
7. My cylinder is about 3" diameter or the piston has a dia of about 2 3/4 inches. This is an area of 6 sq in.
8. To put out a force of about 3600 lbs on 6 sq in you need a pressure from the pump of 600 psi. The book says the pump is good for up to 3000 psi so it looks OK so far.
9. The relief valve is set over 600 psi and I wish I could call the factory, let us guess that it is 1200psi give or take. Note that 1200 psi over 6 sq in is a force of 7200 lbs or 3.6 tons. A bunch.
10. If the relief valve is stuck or jammed the pump could put out 3000 psi. Over 6 sq in this is 18000 lbs or 9 tons. Think Godzilla under the trailer grinding things up!
Considerable forces. I can now see that if the cylinder gets jammed or stuck, there are considerable forces generated the could easily bend or distort guide rods and cylinders. In Part III I will try to explain what I found in my removal, repair process. How can these rods get so bent up? More later.
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